3x^2-5x=4-3x^2

Solution for 3x^2-5x=4-3x^2 equation:

3x^2-5x=4-3x^2

We move all terms to the left:

3x^2-5x-(4-3x^2)=0

We get rid of parentheses

3x^2+3x^2-5x-4=0

We add all the numbers together, and all the variables

6x^2-5x-4=0

a = 6; b = -5; c = -4;
Δ = b2-4ac
Δ = -52-4·6·(-4)
Δ = 121
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{121}=11$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-5)-11}{2*6}=\frac{-6}{12}
=-1/2
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-5)+11}{2*6}=\frac{16}{12}
=1+1/3
$